Example 2 – cont’d
n#include <iostream.h>
n    #include <iomanip.h>
n int main() {
n   cout << setw(3) << 6    << endl
n     << setw(3) << 18   << endl
n     << setw(3) << 124  << endl
n     <<"---" << endl << (6 + 18 + 124) << endl;
n     return 0;
n}
n  6
n   18
n 124
n ---
n 148
n
Since setw(3) field width manipulators are given, cout allocates 3 spaces for each number as it is received